So one of the questions is: How many mL of a 0.280 M K2Cr2O7(aq) solution are needed to reduce 1.40 g of sulfur? The equation is K2Cr2O7 + H2O + S > SO2 + KOH + Cr2O3. And I vaguely remember needing to find a ratio and using a formula with n/v or something, but I cant remember the specifics. Help please?
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